How to generate armstrong number with in a range
#include<stdio.h>
void main(){
int num,r,sum,temp;
int min,max;
printf("Enter the left range: ");
scanf("%d",&min);
printf("Enter the right range: ");
scanf("%d",&max);
printf("Armstrong numbers in given range are: ");
for(num=min;num<=max;num++)
{
temp=num;
sum = 0;
while(temp!=0){
r=temp%10;
temp=temp/10;
sum=sum+(r*r*r);
}
if(sum==num)
printf("%d ",num);
}
}
1 comments:
I also find an example of source code of generate armstrong numbers ：
Armstrong number in c: This program prints armstrong number. In our program we ask the user to enter a number and then we use a loop from one to the entered number and check if it is an armstrong number and if it is then the number is printed on the screen. Remember a number is armstrong if the sum of cubes of individual digits of a number is equal to the number itself. For example 371 is an armstrong number as 33 + 73 + 13 = 371. Some other armstrong numbers are 0, 1, 153, 370, 407.
C programming code
#include
int main()
{
int r;
long number = 0, c, sum = 0, temp;
printf("Enter an integer upto which you want to find armstrong numbers\n");
scanf("%ld",&number);
printf("Following armstrong numbers are found from 1 to %ld\n",number);
for( c = 1 ; c <= number ; c++ )
{
temp = c;
while( temp != 0 )
{
r = temp%10;
sum = sum + r*r*r;
temp = temp/10;
}
if ( c == sum )
printf("%ld\n", c);
sum = 0;
}
return 0;
}
Post a Comment
You are most welcome for making comments here. I will consider your view and will reply you soon.